| A | B | C | D | E | F | G | H | I | J | K |
| 2 | ||||||||||
| 3 | a) | |||||||||
| 4 | Calculation of monthly payment: | |||||||||
| 5 | Loan Amount | $ 27,000.00 | ||||||||
| 6 | Duration of loan | 60 | Months | |||||||
| 7 | Monthly Interest rate | 0.50% | ||||||||
| 8 | ||||||||||
| 9 | RATE (Montly interest rate): | 0.50% | ||||||||
| 10 | NPER (No of Months): | 60 | ||||||||
| 11 | PV (Loan Amount): | -$27,000 | ||||||||
| 12 | FV | 0 | ||||||||
| 13 | TYPE | 0 | ||||||||
| 14 | Monthly Payment : | $521.99 | =PMT(D9,D10,D11,D12,D13) | |||||||
| 15 | ||||||||||
| 16 | Hence Monthly payment is | $521.99 | ||||||||
| 17 | ||||||||||
| 18 | b) | |||||||||
| 19 | ||||||||||
| 20 | Calculation of Value of loan: | |||||||||
| 21 | ||||||||||
| 22 | Value of loan will be the present value of all the monthly payments. | |||||||||
| 23 | Monthly Payment | $521.99 | ||||||||
| 24 | Monthly Interest Rate | 0.50% | ||||||||
| 25 | Number of months remaining | 36 | ||||||||
| 26 | ||||||||||
| 27 | ||||||||||
| 28 | Value of loan | =Present value of annuity of monthly payments | ||||||||
| 29 | =521.99*(P/A,0.5%,36) | |||||||||
| 30 | $17,158.20 | =D23*PV(D24,D25,-1,0) | ||||||||
| 31 | ||||||||||
| 32 | Hence Value of loan is | $17,158.20 | ||||||||
| 33 | ||||||||||
| 34 | c) | |||||||||
| 35 | ||||||||||
| 36 | Value of car is $16,000 which is lesser than the value of loan as calculated above. | |||||||||
| 37 | Thus there is negative equity on the loan. | |||||||||
| 38 | Therefore she should keep try to keep the car in good condition so that the equity becomes positive in future. | |||||||||
| 39 | Hence the first option is correct. | |||||||||

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