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5. A steel-belted radial automobile tire is inflated to a gauge pressure of 2.10 x 10° Pa when the temperature is 68 °F. Late

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Answer #1

Given is :-

P1 = 2.10 x 10 PaTi = 68°F or   T = 293.15K

P =??T = 97°F or 12 = 309.261K

Volume is constant throughout the process,

using Ideal gas equation, we get

Pi P2 TT

by plugging all the values we get

P 2.10 x 10°Ра 293,15K 309.261K

which gives us

P2 = 2.21541 x 10 Pa

This is the required gauge pressure at the elevated temperature.

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