Question

Part The balanced reaction for the combustion of ethane is shown in the table. You allow 3.3 mol of ethane (CH) to react with 4.1 mol oxygen (O2). using the Simulation, to indicate the amounts of all chemical species for the initial, change, and final conditions Drag the appropriate amounts to their respective targets. View Available Hint(s)

Answer 1

The solution is attached below:

The bolanced ehemicat veaction fa --- 6H20 2602 4 Co2 ond 3.3 mo omolea f Given, no (Fren owation No. f meles olGH6 Ne moler ef oz egont 4-1 Frem 1-24 melen of zHe No. 3.3 given obvious that 2He in tie limiting regent N emoles reoct = (No. of molo of 2 taken) 3 No. ef moles of CH reoct A. 1-1 moles. e63-3-1.171) meles Un reacted molen 2-129 Ne moler Co2 4 2. Frem equatien 2 No. of meler of C2Ho 2x no. of moles of H 8Teocteo - (2 x 1) moleo 2 2. 342 moles No. mles tf u20 3from equation (4) 2 Ne of meler of (2h6 3K no. ct mnoles of (9 H reocted No reles ot ti20 - - 3 x 1) moles z 3.513 moles

C2H6 CO2 H2O 4. Tnitial 3.3 171 3.513 Cham ge 2 342 4. 3.513 2 342 2.124 final