Question

An athlete holds a 26.2 N pole in equilibrium by exerting an upward force U with her left hand and a downward force D with her right hand as shown. Point C is the center of gravity of the pole. (Let L, 2.25 m, L, = 1.40 m, and L3 0.850 m. Due to the nature of this problem, do not use rounded intermediate values in your calculations-including answers submitted in WebAssign.) L3 L2 L1 U A С В g (a) What is the magnitude of U (in N)? N (b) What is the magnitude of D (in N)? N

Answer 1

L- F: B.D EL, اره ما تم AN 26.2N L = 2-25 m L = 1.4 L3 = 0.850 m a) for equilibrium condition EF = 0 {fy = 0 {P=0 U= DHE Taking to eque about c he have L₂ U = (L2 +23) D solving D L = ( 12 Ju Putting into U= () u + Fg uri- hitte - z = U= 452612 = 69,352 N → U= 69.352N b) D = U-Fg - 69.352-26-2 = 43.152 N + 3 17