Question

stine Hydrochloric Acid Solution with a Standard Sodium Hydroxide Solution ANAL. 425: Titrating Hydrochloric Acid Sol Post-Laboratory Questions se the spaces provided for the answers and additional paper if necessary) UUUUUUUUUUUUU (4) Briefly comment on the procedural problem associated with the titration described in (3). 1. A chemistry student purchased commercially pre- pared muriatic acid for use in cleaning a home swim- ming pool. Realizing that muriatic acid is another name for HCl solution, the student wanted to deter- mine the HCl concentration in the purchased solution. The student took a 10.00-ml solution sample and added it to enough distilled water to make a 250-ml solution. A 10.00-ml sample of the diluted muriatic acid solution required 41.17 mL of 0.1232N NaOH SO- lution for titration to a phenolphthalein end point. (1) Calculate the normality of the diluted muriatic acid solution. 2. A pool-supply store owner recommended that a dry acid powder be used to clean pool filters and ad- just water pH, instead of muriatic acid solution. The dry acid powder is 90.0% sodium hydrogen sulfate (NaHSO4) and 10.0% inert filler. (1) Calculate the number of grams of NaHSO, in 1.00 lb of dry acid powder (1 lb = 453.6 g). (2) Calculate the normality of the undiluted muri- atic acid solution. (3) Calculate the volume, in milliliters, of NaOH solution required to titrate 1.00 mL of the undiluted mu- riatic acid. (2) Write the chemical equation for the neutral- ization reaction between NaHSO4 and NaOH. section date name

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Answer 1

lo ml el diluted muristic aaid lHe solution heauied 41-17mL I. 0. 1232N Naok N=M So nfacte ) (for Naot, Using Stendard Molasty equatua MM-MLV Base Arid M.x lo = 0 1232 x41.17 dil mL ML O.5072 M MA rHc, MN ( ned) = 0.5072 N Normatity oas Caleulate el Caluation Nowmaluby e undiuded Undiluekd ed Mx10 =0.5072 x 250 nL inL Mondul=12.6804 M MEN NUndil =12.68 0y N MV MV 3 L Undiliakd NaoH HCI 12.6804 x1- o.1232 XV = 102.926 mL lo2. 926 ml ruquised to dutiat urolilutad seludtion Naoh is

1. for tatration describad in Molarity of NaoH 0-1232 M Acid l 12.6804M Volune NaoH lo2. 926ML Volume Aeid im Figh asymmetoy in dodesh tave been foud t will h a diticat t tetralien becaue Auid is too lonentratd to ba titraad earily Visualialio end hoint will ba anather challege ocawe Aligut change in volune an brig lage ror in the exhurimest exaet