Question

A satellite is in a circular orbit around the Earth at an altitude of 3.58 x 100 m. (a) Find the period of the orbit. (b) Find the speed of the satellite. km/s (c) Find the acceleration of the satellite. m/s toward the center of the Earth

Answer 1

T + Satellite het height h: 3.58x105m Earth IWKT Rading of earth 6371x103 m MODD of earth 5.972 x 1024kg = M G-2 6.6 7 3x10-11 Nm/kq? Gravila tronal constant Altitude Sheight ) of Satellite) z 3.58 X 10CM We hava velocity of satellite = /GM R heigh of satellite from centre od carth (8.3 71x103) 6 (3.58 x 106 ) 9,951x106 V2 (6.673x10-11X 9.972x10²4 9.951x108 Ve 63 28.3 mis or 6.388 km/s - Epoca Satellite

acceleration in giren by (a) at GM २२ 2 6673x10-1X3.972x1024 49.961740612 ta z 4,02m 153 acceleration Time perrod of orbit io girenby T2 - 4re² R3 GM = 4XC3.14)?x69,951x10C) 3 6673x10"ttx 5.972x1024 T-4875.044 5 I a 2. 74 hr - Time period

The answers for the above questions are solved in the above

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