a) Specific profit function for this position = Profit from writing the put + Profit from buying the put
= P1 - max (K - S1, 0) + 2 x [max (K2 - S, 0) - P2]
= 17.73 - max (330 - S, 0) + 2 x [max (325 - S, 0) - 15.65]
= 2 x max (325 - S, 0) - max (330 - S, 0) - 13.57
b) For break even: the profit function = 0
Case 1: Let's assume S ≤ 325
2 x (325 - S) - (330 - S) - 13.57 = 0
Hence, 320 - S - 13.57 = 0
Hence, S = 320 - 13.57 = $ 306.43
Hence, the break even price = S = $ 306.43
Case 2: Let's assume 325 < S ≤ 330
(S - 330) - 13.57 = 0
Hence, S = 330 + 13.57 > 330
Hence, the original assumption is not met. Hence there is no solution here.
Case 3: Let's assume S > 330
None of the put options will be exercised. Then there will be a net loss. Hence, again there is no solution here.
Hence, the final answer is: the break even price is $ 306.43
c) Maximum potential profit occurs when the stock price S = 0 and the maximum potential profit = 2 x max (325 - S, 0) - max (330 - S, 0) - 13.57 when S = 0 i.e. = 2 x 325 - 330 - 13.57 = $ 306.43
d) Maximum potential loss = $ 13.57 and it occurs at any price S ≥ 330
e) Profit loss table:
| S | Profit |
| 0 | 306.43 |
| 25 | 281.43 |
| 50 | 256.43 |
| 75 | 231.43 |
| 100 | 206.43 |
| 125 | 181.43 |
| 150 | 156.43 |
| 175 | 131.43 |
| 200 | 106.43 |
| 225 | 81.43 |
| 250 | 56.43 |
| 275 | 31.43 |
| 300 | 6.43 |
| 325 | -18.57 |
| 350 | -13.57 |
| 375 | -13.57 |
| 400 | -13.57 |
| 425 | -13.57 |
| 450 | -13.57 |
And the diagram is:

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