Question

10. The MO diagrams of NO and NO+ are similar (see Lecture 15 for the MO diagram of NO+). On the basis of this consideration, respond to the following: (a) Sketch the singly-occupied MO of NO. Ν Ο (b) What is the total number of electrons in the anti-bonding MOs of NO? (c) Do the necessary calculations to decide when the NO bond should become stronger: when this compound undergoes one-electron reduction or oxidation? (d) Which atom in NO should have most electron density of the unpaired electron?

Answer 1

Answer!- C Given that enuation is MO NO The Occupied given M੯ ! *222 Mata 2p 2P ATE TRY IT 2/2 02P 13] 18 m onths MOD NO" W Scanned with CamScanner

The given total of numbers electron in anotin bonding MOOI NO - The number of clatrons in Anti- Bonding Mogot No =2+2+1 ->0:- The given com pound underneas one-Jeltson The Bond onder of No= 1² [cio.o- co A. 8.0] => 2 [10-5] =2.5. for not, B.o= £ [10-2] = b =3. -) The bond onder a Bs bond strength 10. When No undergc05 one deetorom encides ton, No bond becomes stom ger -> The oxygen has most electron to a slike atom in no malese. > So, orygen has electron more ♡ Ics Scanned with CamScanner