Question

A systems analyst tests a new algorithm designed to work faster than the currently-used algorithm. Each...

A systems analyst tests a new algorithm designed to work faster than the currently-used algorithm. Each algorithm is applied to a group of 3333 sample problems. The new algorithm completes the sample problems with a mean time of 24.0524.05 hours. The current algorithm completes the sample problems with a mean time of 27.0127.01 hours. Assume the population standard deviation for the new algorithm is 5.3295.329 hours, while the current algorithm has a population standard deviation of 3.0783.078 hours. Conduct a hypothesis test at the 0.10.1 level of significance of the claim that the new algorithm has a lower mean completion time than the current algorithm. Let μ1μ1 be the true mean completion time for the new algorithm and μ2μ2 be the true mean completion time for the current algorithm.

Step 1 of 5 :  

State the null and alternative hypotheses for the test.

Step 2 of 5: Compute the value of the test statistic. Round your answer to two decimal places

Step 3 of 5: Compute the p value

Step 4 of 5: Determine the decision rule for rejecting the null hypothesis Ho

Step 5 of 5: Make the decision for the hypothesis test.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Here we have : 2. = 33. , = 24.05, S, -50329 n2 = 33, 22 = 27.01, S2 = 3.078 a=0.10 Degreeds freedom (df)= il stay on agrega

Add a comment
Know the answer?
Add Answer to:
A systems analyst tests a new algorithm designed to work faster than the currently-used algorithm. Each...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A systems analyst tests a new algorithm designed to work faster than the currently-used algorithm. Each...

    A systems analyst tests a new algorithm designed to work faster than the currently-used algorithm. Each algorithm is applied to a group of 46 sample problems. The new algorithm completes the sample problems with a mean time of 13.39 hours. The current algorithm completes the sample problems with a mean time of 14.25 hours. The standard deviation is found to be 4.600 hours for the new algorithm, and 3.063 hours for the current algorithm. Conduct a hypothesis test at the...

  • A systems analyst tests a new algorithm designed to work faster than the currently-used algorithm. Each...

    A systems analyst tests a new algorithm designed to work faster than the currently-used algorithm. Each algorithm is applied to a group of 48 sample problems. The new algorithm completes the sample problems with a mean time of 19.90 hours. The current algorithm completes the sample problems with a mean time of 21.33 hours. The standard deviation is found to be 4.320 hours for the new algorithm, and 5.402 hours for the current algorithm. Conduct a hypothesis test at the...

  • A systems analyst tests a new algorithm designed to work faster than the currently-used algorithm. Each...

    A systems analyst tests a new algorithm designed to work faster than the currently-used algorithm. Each algorithm is applied to a group of 48 sample problems. The new algorithm completes the sample problems with a mean time of 19.90 hours. The current algorithm completes the sample problems with a mean time of 21.33 hours. The standard deviation is found to be 4.320 hours for the new algorithm, and 5.402 hours for the current algorithm. Conduct a hypothesis test at the...

  • A systems analyst tests a new algorithm designed to work faster than the currently used algorithm....

    A systems analyst tests a new algorithm designed to work faster than the currently used algorithm. Each algorithm is applied to a group of 60 sample problems. The new algorithm completes the sample problems with a mean time of 22.16 hours. The current algorithm completes the sample problems with a mean time of 24.18 hours. Assume the population standard deviation for the new algorithm is 5.572 hours, while the current algorithm has a population standard deviation of 4.365 hours. Conduct...

  • A systems analyst tests a new algorithm designed to work faster than the currently-used algorithm. Each algorithm is applied to a group of 47sample problems. The new algorithm completes the sample pro...

    A systems analyst tests a new algorithm designed to work faster than the currently-used algorithm. Each algorithm is applied to a group of 47sample problems. The new algorithm completes the sample problems with a mean time of 14.75 hours. The current algorithm completes the sample problems with a mean time of 16.77 hours. Assume the population standard deviation for the new algorithm is 3.956 hours, while the current algorithm has a population standard deviation of 5.135 hours. Conduct a hypothesis...

  • A technician compares repair costs for two types of microwave ovens (type I and type II)....

    A technician compares repair costs for two types of microwave ovens (type I and type II). He believes that the repair cost for type I ovens is greater than the repair cost for type II ovens. A sample of 5656 type I ovens has a mean repair cost of $75.86$⁢75.86, with a standard deviation of $13.29$⁢13.29. A sample of 5656 type II ovens has a mean repair cost of $68.15$⁢68.15, with a standard deviation of $15.61$⁢15.61. Conduct a hypothesis test...

  • A manufacturer claims that the calling range (in feet) of its 900-MHz cordless telephone is greater...

    A manufacturer claims that the calling range (in feet) of its 900-MHz cordless telephone is greater than that of its leading competitor. A sample of 99 phones from the manufacturer had a mean range of 13501350 feet with a standard deviation of 4242 feet. A sample of 1717 similar phones from its competitor had a mean range of 12801280 feet with a standard deviation of 2828 feet. Do the results support the manufacturer's claim? Let μ1μ1 be the true mean...

  • A study was designed to compare the attitudes of two groups of nursing students towards computers....

    A study was designed to compare the attitudes of two groups of nursing students towards computers. Group 1 had previously taken a statistical methods course that involved significant computer interaction. Group 2 had taken a statistic methods course that did not use computers. The students' attitudes were measured by administering the Computer Anxiety Rating Scale (CARS). A random sample of 1111 nursing students from Group 1 resulted in a mean score of 40.840.8 with a standard deviation of 5.45.4. A...

  • A medical researcher wants to compare the pulse rates of smokers and non-smokers. He believes that...

    A medical researcher wants to compare the pulse rates of smokers and non-smokers. He believes that the pulse rate for smokers and non-smokers is different and wants to test this claim at the 0.050.05 level of significance. A sample of 3333 smokers has a mean pulse rate of 9090, and a sample of 5050 non-smokers has a mean pulse rate of 8686. The population standard deviation of the pulse rates is known to be 55 for smokers and 66 for...

  • A technician compares repair costs for two types of microwave ovens (type I and type II)....

    A technician compares repair costs for two types of microwave ovens (type I and type II). He believes that the repair cost for type I ovens is greater than the repair cost for type II ovens. A sample of 56 type I ovens has a mean repair cost of $⁢76.66, with a standard deviation of $⁢18.63. A sample of 75 type II ovens has a mean repair cost of $⁢72.66, with a standard deviation of $⁢22.09. Conduct a hypothesis test...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT