Question

Assume the typical yield for the Co(salen) complex is 78%. If we want to make 3 grams, what is the minimum amount of salicylaldehyde required (in grams and mL).

show me how you are deriving the M.W. of the compound(s) being synthesized (atom count)

Answer 1

__NH₂ `NH₂ Η . + Co(OAC)2.4H20 — OH 1 mole equivalent of ethane-1,2-diamine is reacted with 2 mole equivalent of salicylaldehyde to give SalenH2 complex and further reacting this complex with equimole of cobalt(l)acetate tetrahydrate gives the Co(salen) complex. We need 3g of final complex. Means practical yield =3g And % yield = 78% We know % yield = (practical/theoretical)*100 Theoretical yield = (3*100)/78 = 3.846 g Molecular formula of Co(salen) = C16H14 CON202 atomic mass of C=12.00, H = 1.00, N=14.00, O=16.00, Co=58.93 then Molar mass = (12*16)+(14*1)+(58.93)+(14*2)+(16*2) = 325 g/mol Number of moles of final complex needed = mass/molar mass = 3/325 = 9.23*10^-3 moles To have 1 mole equivalent of complex we need 2 mole equivalent of salicyaldehyde. Then for 9.23*10^-3 mole complex we need = 2*9.23*10^-3 = 18.46*10^-3 mole of salicyaldehyde (molar mass = 122 g/mol). Required mass of salicyaldehyde = mole*molar mass = (18.46*10^-3)*122 g/mol = 2.25 g