Homework Answers
Here Initial kinetic energy given to proton = increase in PE
qV = kq1q2/r
1.6e-19*V = 9e9*1.6e-19*1.6e-19/[1.4e-15 +1.2e-15]
V = 9e9*1.6e-19/[1.4e-15 +1.2e-15]
= 553846 V answer
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HELP PLS!! Problem 2 เร m 5 m o hat s assur icient An unknown element...
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An unknown element has a
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much voltage must be used to accelerate a proton (radius 1.20×10-15
m) so that is has sufficient energy to just penetrate the unknown
element? Assume that the potential is that for point charges.
Problem 2 国8 An unknown element has a nucleus with charge 8.00e and a radius o about 2.00×10-15 m. How much voltage must be used to accelerate a proton radius...
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HELP PLS!!
Problem 2 เร m 5 m o hat s assur icient An unknown element has a nucleus with charge 9.60e and a radius o about 3 energy to just penetrate the unknown element? Assume that the potential is that for point charges. 0 ow muc voltage must be used to accelerate a pro on radius Submit Answer Tries 0/6
Part ch. a carton nucleus? Aarbon noleus has a charp, of + 6eadb, taas s about 27,O-10m st า mast be used to accelerate a proton o adus 12x10-1s m so nat t has นǐ ien ener rto Assume the potential is that for point charges Express your answer to two significant figures and include the appropriate units. Value Units
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