1. A particle with an electrical charge of 3.50 nC is traveling with an instantaneous velocity of 5.00 x 104m/s in the positive x-direction. The particle is in a region of uniform magnetic field of 0.0420 T in the negative z-direction. What is the magnetic force that acts on the particle at this instant?
1. A particle with an electrical charge of 3.50 nC is traveling with an instantaneous velocity...
A particle with a charge of -2.30 x 10^-8 c is moving with an instantaneous velocity of magnitude 39.5 km/s in the x-y plane at an angle of 55 degrees counterclockwise fromthe + x axis. A. what is the direction of the force exerted on this particle by a magnetic field with magnitude 2.00 T in the -x direction. B. what is the magnitude of the force exerted on this particle by a magnetic field with magnitude 2.00 T in...
A particle with a charge of ?1.24×10?8C is moving with instantaneous velocity v? = (4.19×104m/s)i^ + (?3.85×104m/s)j^ .What is the force exerted on this particle by a magnetic field B? = (2.70 T ) i^? Enter the x, y, and z components of the force separated by commas.What is the force exerted on this particle by a magnetic field B? = (2.70 T ) k^? Enter the x, y, and z components of the force separated by commas.
At some time, a charged particle with q = −1.24×10−8C is moving with instantaneous velocity v = (4.19×104m/s) i^ + (−3.85×104m/s) j^. A. The particle is in a magnetic field B = (2.40 T ) i^. What is the force on the particle? Enter the x, y, and z components of the force separated by commas, so your answer should be three numbers. B. What is the force exerted on this particle if the magnetic field is B = (2.40...
A particle with a charge of-2.50 X 10-8 C is moving with an instantaneous velocity of magnitude 40.0 km/s in the xy- plane at an angle of 50° counterclockwise from the +x axis. What are the magnitude and direction of the force exerted on this particle by a magnetic field with magnitude 2.00 T in the (a) -x direction, and (b) +z direction?
A particle with a charge of q = -5.00 nC is moving in a uniform magnetic field of B⃗ =( -1.27 T ) z^. The magnetic force on the particle is measured to be F⃗ =( −7.60×10−7 N )y^. Calculate vx, the x component of the velocity of the particle.
A particle with a charge of -2.50x10-8 C is moving with an instantaneous velocity of magnitude 36.5 km/s in the c-y plane at an angle of 55 counterclockwise from the to axis. Part A What is the direction of the force exerted on this particle by a magnetic field with magnitude 2.00 T in the - direction? O +2 O ty 0 +2 Part B What is the magnitude of the force exerted on this particle by a magnetic field...
An alpha particle has a positive charge that is double the charge of a proton, and a mass of 6.64 x 10- kg. At a particular instant, it is moving with a speed of 5.00 x 100 m/s through a magnetic field. At this instant, its velocity makes an angle of 64 with the direction of the magnetic field at the particle's location. The magnitude of the field is 0.230 T (a) What is the magnitude of the magnetic force...
A particle with negative charge q and mass m = 2.50×10−15 kg is traveling through a region containing a uniform magnetic field B⃗ =(−0.110T)k^. At a particular instant of time the velocity of the particle is v⃗ =(1.10×106m/s)(−3i^+4j^+12k^) and the force F⃗ on the particle has a magnitude of 2.30 N .etermine the acceleration a⃗ of the particle. Find the x-component.Find the y-component.Find the z-component.Explain why the path of the particle is a helix.Determine the radius of curvature R of...
A negatively charged particle, with charge q = 5.10×10−6 C, has a velocity of 416 m/s in the positive x-direction, moves into a region with a magnetic field and an electric field. The magnetic field, has a magnitude of 1.50 T, and is pointing in the positive y-direction. The electric field, has a magnitude of 4.00×103 N/C, and points in the positive z-direction. What is the value of the net force on the charged particle? A. 2.36×10−2 N, negative z-direction...
A particle with a charge of -1.24×10^8 C is moving with instantaneous velocity v= (1.49×10^4 m/s)i + (-3.85×10^4 m/s)j. What is the force exerted on this particle by a magnetic field:(A) B=(1.40 T)i + (-2.30 T)k and;(B) B=(1.25 T)i + (2.00 T)j + (3.50 T)k?