Answer :
If you write y = A cos 2π(x/L+ft) or y = A cos(kx +wt)
where x is distance
t is time
L is wavelength
and f is frequency
Wave speed is f*L.
Compare with the given equation :
y = (2.00 cm) cos[(π/2)(6.47 m-1x - 9.34 s-1t)]
multiply π/2 to inside equation and get
y = (2.00 cm) cos[(π x 3.235 m-1x - 4.67 x π s-1t)]
1) frequency = w/2π
= 4.67 x π/ 2π= 2.335 s-1
2) wavelength = 2π/k = 2π/3.235π = 0.618 m
3) speed of the wave = f x w = 2.335 x 0.618 = 1.44 m/s
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To practice Problem-Solving
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0.550 m . At time t=0, the x=0 end of the string has its maximum
upward displacement. Find the transverse displacement y of a
particle at x = 1.40 m and...
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