Question

insert the product structure for the reactions

Nal + Acetone SN2 (Write the structure Compound below) НнС 1-Chlorobutane CI CI CHз Нс 2-Chlorobutane Br CHз НС 2-Bromobutane НС 1-Bromobutane Br CH3 Н.с CH3 t-butylchloride CI CI Benzylchloride Br Bromobenzene

Answer 1

ne UUUUUUUUUUUU V u + nat acetone. Her ' I + Nace I-chlorobutane SN₂ J-iodo butane The reaction proceeds by sN 2 mechanism. The iodicle ion is a good nucleophile and adds as I I an o o a a - H C CH3 + NaI acetone ~ CH3 + Nace. 2-chlorobutane 2-I odobutane 2-chloro butane is a secondary alkyl halide. Here the leaning group is ce-. Sni and SNy reactions both are difficult .ce- is not a good leaning group because it is a conjugate base of a strong acid and it small compared to Br. As a result is reaction occurs very slowly.

NaI + Br H₃ C CH3 - s Acetone -CH3 + Nabra Her 2- bromobutane 2- iddobutane • Similarly just like 2-chlorobutane, 2-bromo butane is also a secondary alkyl halide but in this case Br- is a good leaning greup and reaction takes place. Nal -NaBr. Hem Br . Acetone H3 3 j-bromobutane. J-io dobutane.