CHem 12 ILI 11. Consider a solution containing 0.100 M fluoride ions and 0.126 M hydroge...

Question

Question

science chemistry

Answer 1

Answer #1

Before adding HCl:

Mol of F- = M(F-)*volume

= 0.100 M * 25.0 mL

= 2.50 mmol

When HCl is added, it will react with F-

Mol of HCl added = M(HCl)*V(HCl)

= 0.01 M * 9.00 mL

= 0.09 mmol

0.09 mmol of HCl and F- will react.

So,

Mol of F- remaining = 2.50 mmol - 0.09 mmol

= 2.41 mmol

Volume of solution = 9.00 mL + 25.0 mL = 34.0 mL

[F-] = Mol of F- remaining / Volume of solution

= 2.41 mmol / 34.0 mL

= 0.0709 M

Answer: 0.0709 M

Answer 2

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