Question

Complete and balance the following neutralization reaction, name the products, and write the net ionic equation 1st attempt Part 1 (1 point) See Periodic Table See Hint Complete and balance the reaction. X X Hel . Al(OH)3(s) + HCl(aq) -

Answer 1

solution =) past 1 Al(OH) (s) + HCl (aq) - Alcez + H2O (aa) (2) when Al(OH)3 react with He then produce Aluminium chloride (Alcez) and H2O (wares). so, ALCOH (s) + Hel (aq) - Alce3(aq) + H20 (4) First balance the ce in bath side. Al(OH)₃ (6) + 3HCl (aq) - Allez (aq) + H20ce) Then Balance the hydrogen (H) in both side. Ano Ae (OH)3 (5) + 3hce (99) > Alcez @9) + 3 H2Oce). This is complete balance reaction. Aluminium Chloride. (part 2 = Other product is (Alcez)

part-3 +3 - ALCOH(s) + 3 HCl (aq) - Alce (aq) +372069) only aqueous (aq) breaks into ions so, Al COH)3 (5) +3+7+36€ → Alt +36€ + 3H30 () (aq) (99) (aq) (aq) cancel out the same ion (3ct) in both side so, net ionic reaction is. Al CoH)3) + 3H+09) > Altiaq) + 3 H3 0() Ans: