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8. [H3O+] = 4.3 x 10-3M Instructions: Calculate the [H3O+] of solutions a and b; calculate the [OH-] solutions c and d. 9. pH


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Answer #1

11)

Given:

pOH = 3.65

use:

pOH = -log [OH-]

3.65 = -log [OH-]

[OH-] = 2.239*10^-4 M

Answer: 2.24*10^-4 M

12)

Given:

pOH = 6.87

use:

pOH = -log [OH-]

6.87 = -log [OH-]

[OH-] = 1.35*10^-7 M

Answer: 1.35*10^-7 M

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