Question

ent PRINTER VERSION BACK Chapter 06, Problem 85 A water slide is constructed so that swimmers, starting from rest at the top of the slide, leave the end of the slide traveling horizontally. As the drawing shows, one person hits the water 5.00 m from the end of the slide in a time of 0.409 s after leaving the slide. Ignore friction and air resistance, find the height in the drawing. Number Units the tolerance is +/-2% Click if you would like to Show Work for this question: Weers SAVE FOR LATER SUBMIT ANSWER Question Attempts: Unlimited

Answer 1

sol) we are given that the swimmer travelled a horizontal distance of sm in 0.409 sec which means un= 5 = 12.225 mls. 0.409 and we are given initially there was no velocity in vertical direction, when falling from slide. So we can calculate Ug = agt - gt y = (9-8) (0.409) € 4 must so we have velocaty before hitting the water ve just vag - 12-225² tuje Tuz 12.86 mis] of Now we can apply conservation energy as Imuz + (6) mgH to HP 29 12-8612 2 (9.8) 8.uum

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