Question

2) Write the equilibrium constant expressions for each of the following reactions. (For gas-phase reactions, write the Ke expression.) a) 2 NO(g) + O2(g) = 2 NO2(g) b) 4 Ag(s) + O2(g) + 2 Ag2O(S) c) CaCO3(s) + CO2(aq) + H2O(l) = Ca2+(aq) + 2 HCO3(aq) 3) a) Write the K, expressions for reactions a and b in problem 2. b) If the value of K for reaction a in problem 2 is 2.8 x 1011 at 200°C, what is the value of Kp at this temperature?

Answer 1

concentration of NO 2. a) 2 NO(g) + O2 (8) = 2 N02 (8) [NO] Ke = [Noz] . of Mary [no]*[or] [no].» Comentation [09] » komentali ) 40g (9) +02 (3) = ang,0 () fº3 ke - I trahim

2960319 Coman) +420) = 6987104) + 2 H2oz (ae). In systems that involve components of afferent phase, such as gelial and gasso, liquid and gases er selation an gure liquid, the concentration for the pure Substances (liquid or solid) are not included in the expression of equilitrium Constant (ke). as the concentration of pare Substances are constant, aqueles up the quantity. In this case are considered Ksp instead of ke. 56224] [Hers']2 ase [com] [ tteo] soe] come out [the] - loan ang 3. og Kp = Ke (RT) *** a) KP for 2N0(8) +03(:) = PNoy (0) Prog Partial pressure of No Kp = P2 Pro - Partial pressure b) Kip for 4 A9 () +02 (1) 28g 20 ( 1. kp = h . Poz Parkal pressure

3.01) Kp = Ke (87) ** Ke = 9.8X10" R = 0.0821 fit atm.. maí T= 673 +200) * 1. = 473K An for ano (8)+09 (1) § 210218) w: 2-2-1 = -1 AN = moles of gaseous Rodents - boules of Je to

Kp = (2.8x10 " uit ma') (0-060) Estetica molt ) = (2+8x10 "* 0-9821) tid med god atm. myli = 0.22988 X10"atm x 473 = 9.2988 x 10' atm. X 473 = 1.097 x 1013 atm X 473