Titration of 20.00mh of a 1000m. • Find the pH during the thiethylamine (CH₃ CH2) 3N...

Question

Question

science chemistry

Answer 1

Answer #1

Since both solution have same molarity so equal volume of both solution will be required at equivalence point.

Et₃ N ( aq) + HCl ( aq) $\rightarrow$ Et₃NH ⁺(aq) + Cl ^- ( aq)

Where Et = CH3CH2

Since Triethylamine is a weak base it's conjugate ion will hydolyse and make solution acidic

[ Et3NH ⁺ ( aq) ] = 20 mL x 0.1 M / ( 20 + 20 ) mL = 0.05 M

Et3NH⁺ ( aq )+ H2O ( l ) $\Leftrightarrow$ Et₃NH ⁺ ( aq )+ H3O ⁺ ( aq)

Hydrolsis constant ( Kh ) = Kw / Kb

= 10^-14 / 5.2 x 10^-4= 1.92 x 10^-11

P^H = (1/2 )( p^kh - log c )

= ( 1/2 ) ( - log 1.92 x 10^-11 - log 0.05 )

= 6.01

Answer 2

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