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QUESTION 7 Consider the reaction: 2 NO(g) + 2 H2(g) → N2(g) + 2 H2O() for which AH° =-752.2 kJ and AS9 = -351.6 J/K at 298.15

need help with 7 please

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Answer #1

Answer

b) 5314 J/K

Explanation

2NO(g) + 2H2(g) ------> N2(g) + 2H2O(l)

∆S°sys = -351.6J/K

∆S°surr = -∆H°/T = - ( -752.2kJ) / 298.15K = 2.523kJ/K = 2523J/K

∆S°univ = ∆S°sys + ∆S°surr

∆S°univ = - 351.6J/K + ( 2523J/K) = 2171.4J/K

∆S° univ for four moles of NO = 2171.4J/K / 1mol × 2.447mol = 5314 J/K

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