Question

-CHE 109 (Sections 007-012) - Fall19 - STEELMAN > Activities and Due Dates > 95/900 Resources Hint Assignment Score: Check Answer < Question 5 of 9 > Consider the neutralization reaction 2 HNO, (aq) + Ba(OH), (aq) — 2H,O(1) + Ba(NO3), (aq) A 0.105 L sample of an unknown HNO, solution required 40.9 mL of 0.150 M Ba(OH), for complete neutral the concentration of the HNO, solution? concentration:

Answer 1

moles of Ba(OH)2 = 40.9 x 0.150 / 1000

                              = 6.135 x 10^-3 mol

moles of HNO3 = 2 x moles of Ba(OH)2

                         = 2 x 6.135 x 10^-3

                         = 0.01227 mol

moles = Molarity x volume

0.01227 = Molarity x 0.105

Molarity = 0.1168 M

concentration = 0.117 M