Question

Part A and B please

1. (18.3.25) Point charges of 5.00 C and -3.00 pC are placed 0.250 m apart. (a) Where can a third charge be placed so that the net force on it is zero? (b) What if both charges are positive?

Answer 1

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q_1 = 5 mu c q_2 = -3 mu c d = 0.25 m a) let at a distance �x� from charge - 3 mu c where electric force is zero k q_1 q/(d + x)^2 - k q_2 q/(x^2) = 0 5/(0.25 + x)^2 = 3/x^2 Rightarrow (0.25 + x/x)^2 = 5/3 Rightarrow 0.25 + x/x = squareroot 5/3 Rightarrow x = 0.85 gm from - 3 mu c charge b) If both are positive then in between them net force will be zero let at a distance �x� from 5 mu c net force zero k (5)/x^2 = k (3)/(d - x)^2 Rightarrow 0.25 - x^�/x = squareroot 3/5 Rightarrow x^� = 0.141 m