5. What are E cell and AG of a redox reaction at 25 °C for which...

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Question

5. What are E cell and AG of a redox reaction at 25 °C for which n= 1 and K = 5.0 x 104?

science chemistry

Answer 1

Answer #1

$\Delta$ G^o = - 2.303 RT log K ; where R is universal gas constant, T is absolute temperature and K is the equilibrium constant.

Given T= 298 K (25⁰ C)

K = 5.0*10⁴ and we know

R= 8.314 J/mol.K

$\Delta$ G^o = -2.303* 8.314 J/mol.K *298 K* log (5*10⁴) = -26811.61 J/mol

Again $\Delta$ G^o = -n.F.E^o_cellwhere n= 1 (given), F= 96500 C, $\Delta$ G^o = -26811.61 J (calculated)

E^o_cell = -( $\Delta$ G^o/ nF) = -(-26811.61/ 1*96500) = 0.278 J/C = 0.278 V

If you still have any confusion feel free to ask.

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Answer 2

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