Homework Answers
d) 9.0 N
given
m = 0.75 kg
mue_s = 0.82
let F is the applied force required.
The maximum static friction acting on the block,
fs_max = F*mue_s
in the equilibrium net force actin on the block, Fnety = 0
fs_max - m*g = 0
fs_max = m*g
F*mue_s = m*g
F = m*g/mue_s
= 0.75*9.8/0.82
= 8.96 N
= 9.0 N (when rounded to two significant figures)
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