(a) What is the average kinetic energy of hydrogen atoms on the 5500°C surface of the...

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Question

(a) What is the average kinetic energy of hydrogen atoms on the 5500°C surface of the Sun? (b) What is the average kinetic en

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Answer 1

Answer #1

Solution)

Part a)

Given, temperature, T=5500+273=5773 K

We know, Average kinetic Energy=(3/2)*K*T

=(3/2)*(1.38*10^-23)*(5773)= 1.2*10^-19 J (Ans)

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Part b)

Here, also, Average Kinetic Energy= (3/2)*k*T

=(3/2)*(1.38*10^-23)*(1.1*10^6)=2.27*10^-17 J (Ans)

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Answer 2

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