
answer this using SAS program by ANOVA
Solution
Part (a)
Paired t-test
Let X = Zinc concentration (in mg/L) at the bottom of the location
Y = Zinc concentration (in mg/L) at the surface of the location
And D = X – Y.
Then, D ~ N(µ, σ2) where σ2 is unknown.
Claim:
Mean zinc concentration (in mg/L) at the bottom is greater than that at the surface.
Hypotheses:
Null: H0: µ = µ0= 0 Vs Alternative: HA: µ > 0 [claim]
Test Statistic:
t = (√n) (Dbar - µ0)/s where
Dbar and s are respectively, sample average and sample standard deviation based on n observations on X and Y.
Calculations
Summary of Excel calculations is given below:
|
Location (i) |
xi |
yi |
di |
|
1 |
0.43 |
0.415 |
0.015 |
|
2 |
0.266 |
0.238 |
0.028 |
|
3 |
0.567 |
0.39 |
0.177 |
|
4 |
0.531 |
0.41 |
0.121 |
|
5 |
0.707 |
0.605 |
0.102 |
|
6 |
0.716 |
0.609 |
0.107 |
|
n = |
6 |
|
dbar |
0.091667 |
|
s(d) |
0.060688 |
|
µ0 |
0 |
|
tcal |
3.699834 |
|
α = |
0.05 |
|
tcrit = |
2.015048 |
|
p-value = |
0.007001 |
Distribution, Critical Value and p-value:
Under H0, t ~ tn - 1. Hence, for level of significance α%, Critical Value = upper α% point of
tn - 1 and p-value = P(tn - 1 > tcal).
Significance level: 5% [i.e., 0.05 - given]
Using Excel Functions: Statistical TINV TDIST, the above are found to be as given in the above table.
Decision:
Since tcal > tcrit, or equivalently, p-value < α, H0 is rejected. Answer
Part (b)
Conclusion:
There is sufficient evidence to suggest that the claim is valid. i.e., Mean zinc concentration (in mg/L) at the bottom is greater than that at the surface. Answer
DONE
answer this using SAS program by ANOVA 2. Trace minerals in drinking water affect the taste....