Question

One of the duties of police officers is to enforce laws in society. How do you measure that police officer enforce laws in society from a scale of 0 (never enforces the law) to 10 (always enforces the law)? a. the x bar = 8.75, sigma = 1.25, n=400 CL % 90, 95, 99, 99.9 Alpha Significance (a) .10, .05, .01, .001 Z score 1.65, 1.96, 2.58, 3.27

Answer 1

Sol:

confidence interval for mean is given by

xbar-z*sigma/sqrt(n),xbar+z*sigma/sqrt(n)

90% confidence interval for mean enforce law scale

8.75-1.65*1.25/sqrt(400),8.75+1.65*1.25/sqrt(400)

8.646875,8.853125

90% lower limit mean enforce law scale=8.646875

90% upper limit mean enforce law scale=8.853125

95% confidence interval for mean enforce law scale

8.75-1.96*1.25/sqrt(400),8.75+1.96*1.25/sqrt(400)

8.6275,8.8725

95% lower limit mean enforce law scale= 8.6275

95% upper limit mean enforce law scale= 8.8725

99% confidence interval for mean enforce law scale

8.75-2.58*1.25/sqrt(400),8.75+2.58*1.25/sqrt(400)

8.58875,8.91125

99% lower limit mean enforce law scale=  8.58875

99% upper limit mean enforce law scale=  8.91125

99.9% confidence interval for mean enforce law scale

8.75-3.27*1.25/sqrt(400),8.75+3.27*1.25/sqrt(400)

8.545625,8.954375

99.9% lower limit mean enforce law scale=  8.545625

99.9% upper limit mean enforce law scale=  8.954375