Question

An ideal gas expands isobarically from point 1 to point 2 as illustrated in the figure below 0 0 V2 0 Vl If the work done by the gas w=26711), initial temperature T=225.6K, n=5.0mols, and initial volume И=1.9m, what is the final volume ½? Answer in cubic meters

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Answer #1

Here,

PV = nRT

P1 = nRT / V1

P1 = 5*8.314*225.6 / 1.9

P1 = 4935.9 Pa

we know

work done is area under the graph

W = (4935.9 - 0) * (V2 - 1.9)

26711 = 4935.9 * V2 - 9378.2

V2 = 7.311 m3

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