Question

13) The base-mediated E2 elimination of HCl from molecule A requires the hydrogen shown and the chloride leaving group to be antiperiplanar. Base --ВHсr H O' : B Through consideration of appropriate chair conformations, explain with diagrams the relative rate of this elimination when X = H vs X = Bu (10)

Answer 1

X=tsu ΧΞΗ My to Slow / fast S Bese high because * The rate of first reaction where X=H wil gh because here no xteric hinder once for base anyal which is there for and reaction wh X= AB4 Reason is steric hinderance of tou which makes difficult amival of base towards substrate, Because anti H and x group is in some side. 14) Bond angle in cyclo alkome. 120° 108 Cyclohexome, 90° less yclobutane Cyclopentene le cyclop sopome cyclobutane cyclopentane As the bond angle increases molecule feel strain and get stablized. Newmainn projection A A A A a order of strain CS scanned witorder of stability CamScanner

Not Rigid at Normal temperceture * Here molecule is flexible to rotate its bond, as a result axical and equito al bond are equal accessable Hence molecule is chire Rigid at toro temperature * At low temp. only above 2 conformer are possible which are mirror image of each other. Because Renow : bond rotation is stopped. Hence it is racemic mixture now. Scanned with CamScanner