Question

1#4 In a purely inductive AC 1 Circuit, L = 25.0mth and the rms Voltage of 1500. Calculate the inductive Reactance I and the ims Current in the Circuit is 600Hz. I if the frequency is a 6 If the frequency increases to 6.0kHz, what happens to the rms Current in the Circuit ?

Answer 1

Solution) L = 25 mH = 25×10^(-3) H

Vrms = 150 V

(a) f = 60 Hz

Inductive reactance , XL = ?

XL = wL = (2(pi)f)L

XL = (2(pi)60)25×10^(-3)

XL = 9.42 ohms

Rms current , Irms = ?

Irms = (Vrms/XL)

Irms = (150)/(9.42)

Irms = 15.9 A

(b) f = 6 KHz = 6×10^(3) Hz

XL = (2(pi)f)L

XL = (2(pi)×6×10^(3))(25×10^(-3))

XL = 942.47 ohms

Irms = (Vrms)/(XL)

Irms = (150)/(942.47)

Irms = 0.159 A

So rms current decreases .