Homework Answers
the condition for minimum intensity at P, when
the path difference is a multiple of half wavelengths, is given
by,
where n can again take on integer value, n = 0, 1, 2, 3...
Now for third dark fringe putting n=2 we get
Sin© =(5×980×10-9)/2×0.000125
»Sin© = 0.0196
» © = 1.12°
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