Question

2. If 0.100 L of 0.0015 M MgCl2 and 0.200 L of 0.025 M NaF are mixed, should a precipitate of MgF2 form? MgF2 (s) - Mg2+ (aq) + 2 F (aq) Ksp = 3.7 x 10-8 A) no ,it won't occur precipitate B) not enough information C) yes ,it will form precipitate

Answer 1

Page No.1 Date Expt. No. Girtn for Mg ch Volume =O.6010M Comc for Na f Volume 0 2001 1 0.025M Conc for Mg f ksp 3- 7x10-8 Solution:- Let solubiliby gg (moles Litre 21 Mg fre) Soubili by Mgap Fla2) 2t 25 11 2 (selabilyo of Mg") (solubility f ksp (S)C282 ksp kap Ksp Ksp Teacher's Signature

Date Expt.No. Page No.2 3-7 l0- 41 (o.925 x 10- 2.5)x 2.413 X 1o- moles L Salub kity af Mgl 002433 m oles L I water

Date Page No. 3 Expt. No 2Na l ac t2 Naf J Voluume = 0 10 L 0.2 00L 30L Conc 001SM Por MgChy MqCls + 2ce 2C C cenc Concentration H Concentration O.00) 0.0015mole L o1 moles of Mg Soluton IOO15 male no per L metes of Mg O1 100L Salubn no ISoox 10 moles moles 0.00015 Na A Por Nat +2f Na P C 2 C cene Plounde lans Cencentrabion 2X cone Na A 1 Teacher's Signature

Page Clencentration 2 X00025 H O.OSM O.OSMoles L moles lo no' 0.05Mles dution Per L meles f lon molas OO0 XT 200 lution In 0 260L 5 X10 X 20D X 1 mdes moles FO.O1 mo les

Page No. Date Expt. No. FOr Ma t Cencentration Sclute mdes shution CL) Ncdume Cenc mdes Vrume + no 11 Con mixing Hguf aud Nav 1scution L) 0100015 meles t 0.01 moles O.100L + 200L O.0l01s moles 0.3 o0L 0.0338 3 moles I L DEes M 0.033 3 for dilute slutiens Cencentration sdlubility O.D338 3 moles /L Solubilily q MyB Mg fslubility O.0342 ma1les |L 3.1 X10 Jn water f sdwent Cho) In IL means maximum CMgf) that cau be disidred amount salute wathout precip tation 00242 3 moles

have amount o But in sotveut Cko) IL MOf This amouut 0.03383 meles required fo more than dhat s Aaubilrey Dyferauce =Co.03313 -0.02 0.0091 moles This excess ameunt ot Hah ul precipi tale but we mix o 100L 01 0.00 IS M Ma aud o.2001L 0.025M Na f , preapitationMa mll occr ye, t will foom trecipi tate COrrect phont(