Homework Answers
a)The voltage across lamp is:
V = 2.4 V
since S2 is open, current flows through lamp only, I = 0.6
R = V/I = 2.4/0.6 = 4 Ohm
hence, R = 4 Ohm
Req = R1 + Rlamp
I = 6V/Req
Req = 6/0.6 = 10
R1 + Rlamp = 10 => R1 = 10 - 4 = 6 Ohm
Hence, R1 = 6 Ohm
c)The brightness remains same for this case, as no circuit element is connected to the branch containing S1.
b)When the switches are open, the total resistance of the circuit is less and more current is flowing in the circuit and more power dissipation occurs so the bulb is brighter when both the switches are closed as compared to both switch are closed.
c)R2 = 4 Ohm
R1 = 4 x 4/(4 + 4) = 2 ohm
Req = 2 + 6 = 8
I = 6/8 = 0.75 A
I = 0.75 A
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