Question

4. 2 points A molecule has two rings, three double bonds, and two triple bonds. How n does this molecule have?
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Answer #1

Degree of Unsaturation (DoU) for cyclic ring = 1

DoU for double bond = 1

DoU for triple bond = 2

DoU present in the given molecule = 2 + 3 + (2 x 2) = 9

Total DOU in the given molecule = 9

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