Question

(g) Mass of crude 4-tert-butylcyclohexanol Mass of empty beaker grams Mass of beaker + crude 4-tert-butyleyclohexanol grams (next week) Mass of crude 4-tert-butyleyclohexanol grams (next week) 2. Based on your experimental data, what is the theoretical yield of your product 4-tert-butylcyclohexanol? This number should be calculated from the actual amounts that you measured out. Be sure to show all labeled mole ratios. Theoretical Yield = grams 3. What was the percent yield of 4-tert-butylcyclohexanol that you obtained? Percent Yield
mass recovered 0.879grams

1.200grams of the reactant was used

Answer 1

* Reactions H2 Catalyst Intert butyl cyclohexanol wenigmimo gr/med 4-tert Butye- cyclohexanone 154.25 7 molar mass of 6-tert butyl cyclohexanone olar mass of 4-tert butyl cyclohexanol = 156.27 2) Actual yield =0.879 gm In this is Reaction Reaction 0.879 gm produced produ product of antert butyl cyclohexanol, so it is Actual product (yield). ² calenlate Theo. yield : from reaction : 154.25 gms of 4-text Butyl? Produced 156.27 gora of Cyclohexanone Atert Butye- t : cyclohexanol I then 1.200 gms of 4 - text butyl cyclohexanone gm gms of 4-tert Butyl a a 156,27 gm X 1.200 Eyclohexanol - 154.25 gms = 1.215 gma Theo yield

3) Calellate % yield % yield - Actual yield x 100 The orizical viend . where actual yield = 0,879 gins to yield = 0.879 x 100 Theo. yield = 1.215 gms 1.215 1 % yield - 72.34 %.