Question

a) Look at example 15.9 (in the ppt lecture for chapter 15, slides 82-84) in which a leg is modelled as a physical pendulum.Example 15.9 A Swinging Leg as a Pendulum EXAMPLE 15.9 A swinging leg as a pendulum A student in a biomechanics lab measuresExample 15.9 A Swinging Leg as a Pendulum EXAMPLE 15.9 | A swinging leg as a pendulum SOLVE The moment of inertia of a rod pi

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Answer #1

frequency = 1/2pi*sqrt(g/L)
= 1/2pi*sqrt(9.8/0.9)
       = 0.525 Hz
         
Time Period = 1/f = 1/0.525 = 1.9 s

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a) Look at example 15.9 (in the ppt lecture for chapter 15, slides 82-84) in which...
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