Question

I need answer in terms of meters.

A 2000 (lb) sports car collides into the rear end of a 5000 fib) SUV stopped at a red light. The bumpers lock, the brakes are locked, and the two cars skid forward 15.0 [) before stopping. The police officer, knowing that the coefficient of kinetic friction between tires and road is 0.85, calculates the speed of the sports car at impact. What was that speed? coming - 2772,72

in terms of meters and kilograms not ft, lbs

Answer 1

I lb = 0.454 kg ift - 0. 305 melne So wearg Mass of sports car - M Sport a loob 2000lb e m Sport - proox0.454 Mopent = k06 X 09548 & 907.18 kg Map of Suv Car - msuva 5000 lb msun= 5000X 0.454 = 2267.96 kg Car slides distanse s= 15ft - 15X0.305 a 4.572 metre N = fm spurt tm suv) g sport- I sun 4.572 m N Im spart tm suulg let speed of spored spert Car way o il After colliding two cars slide together and forction works on Both ear and car spstops after Isft. so intial energy = energy lost by work done due to friction I m spert v2 = fkis Imspert 02 = Me Nos > Mk (msport msuv) g. s Am spelarelo-x 907.18 XO?= 0.85 (907.18 + 2267.96)*9.884.572 11209 24.44X2 wa H 907.18 may = 16.33 m/s To = 16.33 m/