Homework Answers
Ans:
Test for equal variances:
F statistic=0.750^2/0.683^2=1.206
df1=10-1=9
df2=10-1=9
p-value=fdist(1.206,9,9)=0.3925
As,p-value is high,we fail to reject the null hypothesis.
There is not sufficient evidence to conclude that the two variances are not equal.
Add Answer to:
The Minitab output for the packing me u p Two-Sample T-Test and CI: New machine, Old...
Quiz 6: The Minitab output for the packing time example is as follows: Two-Sample T-Test and...
Quiz 6: The Minitab output for the packing time example is as follows: Two-Sample T-Test and CI: New machine, Old machine Two-sample T for New machine va 0ld machine StDev 42.140 0.683 0.750 SE Mean 0.22 0.24 N Mean New machine old machine 10 43.230 10 Difference u (New machine) H (0ld machine) Estimate for difference: -1.090 T-Test of difference 0(vs ): T-Value -3.40 P-Value 0.003 DE= 18 Both use Pooled StDev 0. 7174 Test the variances of this test.
Stat 210 Quiz 6: The Minitab output for the packing time example is as follows: Two-Sample...
Stat 210 Quiz 6: The Minitab output for the packing time example is as follows: Two-Sample T-Test and CI: New machine, Old machine Two-sample for New machine vs old machine Mean St Dev SE Mean 42.140 0.683 0.22 43.230 0.750 0.24 10 10 New machine old machine (old machine) Difference = u(New machine) - Estimate for difference: -1.090 18 -value = -3.40 P-Value - 0.003 DY 1 st OE CELOzence (VSP Both use pooled St Dev=0.7174 - Test the variances...
! Required information The following MINITAB output presents the results of a hypothesis test for a...
! Required information The following MINITAB output presents the results of a hypothesis test for a population mean u. One-Sample Z: X Test of mu = 45 Vs > 45 The assumed standard deviation = 5.0921 95% Lower Bound 45.5015 Variable X N 122 Mean 46.2598 St Dev 5.0921 SE Mean 0.4610 Z 2.73 P 0.003 0.003 NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Use the output...
The MINITAB printout shows a test for the difference in two population means. Two-Sample T-Test and...
The MINITAB printout shows a test for the difference in two population means. Two-Sample T-Test and CI: Sample 1, Sample 2 Two-sample T for Sample 1 vs Sample 2 N Mean StDev SE Mean Sample 1 6 28.00 4.00 1.6 Sample 2 9 27.86 4.67 1.6 Difference = mu (Sample 1) - mu (Sample 2) Estimate for difference: 0.14 95% CI for difference: (-4.9, 5.2) T-Test of difference = 0 (vs not =): T-Value = 0.06 P-Value = 0.95...
Two-Sample T-Test and CI: height, gender
Two-sample T for height gender N Mean StDev SE Mean male 19 5.73 0.51 0.117 female 24 5.25 0.47 0.096 Difference = mu (male) - mu (female) Estimate for difference: 0.48 90% lower bound for difference: 0.283 T-Test of difference = 0 (vs >): T-Value = 3.17 P-Value = 0.002 DF = 18 Fill in the blanks: Ho: Ha: Type of test: t- test – SRS, Normal ?=?=.05 t-value = P-value: look up on your t-table Decision: Conclusion:
F) Given the Minitab output below: Two-Sample T-Test and Cl: height, gender Two-sample T for height...
F) Given the Minitab output below: Two-Sample T-Test and Cl: height, gender Two-sample T for height gender male female N 19 24 Mean St.Rex 5.73 0.51 5.25 0.47 SE Mean 0.117 0.096 Difference = mu (male) - m (female) Estimate for difference: 0.48 90% lower bound for difference: T-Test of difference - 0 (vs >): T-Value - 2.335 p-Value - 0.015 DE - 18 Fill in the blanks: a. Ho: Ha: 3
QUESTION 9 A firm is studying the delivery times for two raw material suppliers. The firm...
QUESTION 9 A firm is studying the delivery times for two raw material suppliers. The firm is basically satisfied with its current supplier A but would like to compare its delivery time to that of a competitor (supplier B). If the delivery time of A is longer than that of the firm will began making raw material purchases from supplier B. The firm samples 10 deliveries from supplier A and 10 deliveries from supplier B Using the.01 level of significance,...
is that enough for you Two-Sample T-Test and CI: 2011, 2012 Two-sample T for 2011 vs...
is that enough for you
Two-Sample T-Test and CI: 2011, 2012 Two-sample T for 2011 vs 2012 2011 2012 N 75 93 Mean 6.466 6.604 St Dev 0.352 0.398 SE Mean 0.041 0.041 Difference=mu (2011) -mu (2012) Estimate for difference: -0.1376 95% CI for difference: (-0.2535, -0.0217) T-Test of difference=0 (vs not =) : T-Value = -2.34 P-Value=0.020 DF = 166 Both use pooled StDev=0.3782 Manutan International S.A. is a specialist mail-order business providing industrial and office equipment and supplies...
t-Test: Two-Sample Assuming Equal Variances Variable 1 Variable 2 Mean 12.89795918 17.66666667 Variance 161.2185374 567.8266667 Observations...
t-Test: Two-Sample Assuming Equal Variances Variable 1 Variable 2 Mean 12.89795918 17.66666667 Variance 161.2185374 567.8266667 Observations 49 51 Pooled Variance 368.6716646 Hypothesized Mean Difference 0 Df 98 t Stat -1.241549191 P(T<=t) one-tail 0.108683158 t Critical one-tail 1.660551217 P(T<=t) two-tail 0.217366316 t Critical two-tail 1.984467455 Is there a significant difference between the two sample means? If you answer, “yes,” what is your reasoning? If you answer, “no,” what is your reasoning? Please state the conclusion, or your interpretation of the results in terms...
t-test: two-sample assuming equal variances Subject ID Height Mean 9.9 68.85 Variance 39.0421053 35.0815789 Observations 20...
t-test: two-sample assuming equal variances Subject ID Height Mean 9.9 68.85 Variance 39.0421053 35.0815789 Observations 20 20 Pooled Variance 37.0618421 Hypothesized Mean Difference 0 df 38 t Stat -30.621066 P(T<=t) one-tail 1.0856E-28 t Critical one-tail 1.68595446 P(T<=t) two-tail 2.1711E-28 t Critical two-tail 2.02439416 From your results, please report the following: Variable 1 Mean: Variable 2 Mean: Two-tailed p-value: Is your p-value significant? (alpha=0.05) If your results are significant/not significant, what can you conclude from your data? (i.e. is there a...
Quiz 6: The Minitab output for the packing time example is as follows: Two-Sample T-Test and CI: New machine, Old machine Two-sample T for New machine va 0ld machine StDev 42.140 0.683 0.750 SE Mean 0.22 0.24 N Mean New machine old machine 10 43.230 10 Difference u (New machine) H (0ld machine) Estimate for difference: -1.090 T-Test of difference 0(vs ): T-Value -3.40 P-Value 0.003 DE= 18 Both use Pooled StDev 0. 7174 Test the variances of this test.
Stat 210 Quiz 6: The Minitab output for the packing time example is as follows: Two-Sample T-Test and CI: New machine, Old machine Two-sample for New machine vs old machine Mean St Dev SE Mean 42.140 0.683 0.22 43.230 0.750 0.24 10 10 New machine old machine (old machine) Difference = u(New machine) - Estimate for difference: -1.090 18 -value = -3.40 P-Value - 0.003 DY 1 st OE CELOzence (VSP Both use pooled St Dev=0.7174 - Test the variances...
! Required information The following MINITAB output presents the results of a hypothesis test for a population mean u. One-Sample Z: X Test of mu = 45 Vs > 45 The assumed standard deviation = 5.0921 95% Lower Bound 45.5015 Variable X N 122 Mean 46.2598 St Dev 5.0921 SE Mean 0.4610 Z 2.73 P 0.003 0.003 NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Use the output...
F) Given the Minitab output below: Two-Sample T-Test and Cl: height, gender Two-sample T for height gender male female N 19 24 Mean St.Rex 5.73 0.51 5.25 0.47 SE Mean 0.117 0.096 Difference = mu (male) - m (female) Estimate for difference: 0.48 90% lower bound for difference: T-Test of difference - 0 (vs >): T-Value - 2.335 p-Value - 0.015 DE - 18 Fill in the blanks: a. Ho: Ha: 3
QUESTION 9 A firm is studying the delivery times for two raw material suppliers. The firm is basically satisfied with its current supplier A but would like to compare its delivery time to that of a competitor (supplier B). If the delivery time of A is longer than that of the firm will began making raw material purchases from supplier B. The firm samples 10 deliveries from supplier A and 10 deliveries from supplier B Using the.01 level of significance,...
is that enough for you
Two-Sample T-Test and CI: 2011, 2012 Two-sample T for 2011 vs 2012 2011 2012 N 75 93 Mean 6.466 6.604 St Dev 0.352 0.398 SE Mean 0.041 0.041 Difference=mu (2011) -mu (2012) Estimate for difference: -0.1376 95% CI for difference: (-0.2535, -0.0217) T-Test of difference=0 (vs not =) : T-Value = -2.34 P-Value=0.020 DF = 166 Both use pooled StDev=0.3782 Manutan International S.A. is a specialist mail-order business providing industrial and office equipment and supplies...
Most questions answered within 3 hours.
-
Where is the error in this code sequence?
String s1 = "Hello";
String s2 = "ello";...
asked 10 months ago -
Financial data for Joel de Paris, Inc., for last year
follow:
Joel de Paris, Inc.
Balance...
asked 10 months ago -
Consider this reaction:
Al2(SO4)3 (aq)+ BaCl3
(aq) Al2Cl6 (aq)- +
3BaSO4(s) . What is the...
asked 10 months ago -
Suppose that Savneet is considering increasing her
recent random sample from 20 car rentals to 40...
asked 10 months ago -
Trucks arrive at an unloading terminal at an average rate of 120
per hour.
Trucks arrive...
asked 10 months ago -
Why are methanol and ethanol completely soluble in water while
octanol is not very little soluble....
asked 10 months ago -
A facilities manager at a university reads in a research report
that the mean amount of...
asked 10 months ago -
When the CuSO4 is rehydrated by adding water to the anhydrous
compound, is this an endothermic...
asked 10 months ago -
A ray of sunlight is passing from diamond into crown glass; the
angle of incidence is...
asked 10 months ago -
A block of mass 0.249 kg is placed on top of a light, vertical
spring of...
asked 10 months ago -
how do the kidneys compensate in the presences of acidosis
a) trigger hyperventilate
b) reserve acid...
asked 10 months ago -
Question 501 pts
The rental rate of capital to the firm increases. Which of the
following...
asked 10 months ago