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QUESTION 5 10 poin Two identical charges experience a repulsive force of 0.35 N when separated by a distance of 46 cm. What i
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Answer #1

Answer:- Given that 8=46cm=0.46 m F=0.35 nl. Lite = 9x joºmine ... F = 16 2 2 2 = q = (49608²f (0.60 0.35) = 2.89810 9x109 Th

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Answer #2

SOLUTION :


Force between two identical charges q each :

F = k q^2 / (46/100) ^2 = 0.35 N 

=> q^2 = 0.35 *0.46^2 / k 

=> q^2 = 0.35 * 0.46^2 / (8.988 * 10^9) = 8.24 * 10^(-12) 

 [ since, k = 8.988*10^9 n-m^2/C^2 ]

=> q = sqrt(8,24*10^(-12)) 

=> q = 2.87 * 10^(-6) C (ANSWER). 

answered by: Tulsiram Garg
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