Question

What mass of CO2 could be formed by the reaction of 20.0g of CH4 with 88.0 g O2? The balanced chemical reaction equation is

What mass of CO2(g) could be formed by the reaction of 20.0 g of CH4 with 88.0 g 02? The balanced chemical reaction equation is: CH4 + 2 02 → CO2 + 2 H20

Answer 1

The balance equation CH4 + 202- >CQ2 + 2H20 - This means when 1 mole of CH4 reacts with 2 mole of 2 then a mole of CO₂ produce. given zog of chy. 88 g of O₂ - CHG = 20 la mort & O2 = 3 a molt 88 = 1.25 mol = 2.75 mole from balance equation - 0 I mole of cHq required = 2 mole of O₂ 1.25 mole of elty required = 2 x 1-25 R = 215 mole of 02. Howeven we have 2.75 mole of o, i.e. 0.25 mole о, и охим. Altant;, ш сам дау 2 mole of O₂ required = { mole of eltq 2.75 mole of O2 required = £x2.75 of CHE L = 1.375 mole of CH4 Howeven we have only 1.25 mole of cha. le the reaction will be occur upte, Chy is present. - so, the production of co2 depends on the amount of enta. so Theus 1 mole of CHą produce 1 mole of eo, 1125 mule of elta produce = 1.25 mole of co

1 мол 4 02 = 44i- L-25 wоu + 10 = 1' 25 x 44 3 = 554: '. 55 1 4 26, uЩ родии.