Smelting:
CuO(s) + CO(g) ⟶ Cu(s) + CO₂(g)
Part 1:
∆H°f (Cu) = 0 kJ/mol , ∆H°f (CO₂) = -393.5 kJ/mol, ∆H°f (CuO) = -155 kJ/mol, ∆H°f (CO) = -110.5kJ/mol
∆H°rxn = Σ [∆H°f (products)] - Σ
[∆H°f (reactants)]
= ∆H°f (Cu) + ∆H°f (CO₂)
- ∆H°f (CuO) - ∆H°f
(CO)
= [0 + (-393.5)] - [-155 + (-110.5)] kJ/mol
= -128 kJ/mol
Enthalpy change associated with smelting 1.10 moles Cu :
∆H = (1.45 mol) x (-128 kJ/mol)
= -185.6 kJ
Hence, enthalpy change for the reaction recovering 1.45 mol Cu
is -185.6 kJ
Part 2. Recycling:
i) energy required to convert solid Cu to liquid Cu at 25°C:
q₁ = n ∆H°fus
= (1.45 moles) x (13.0 kJ/mol)
= 18.85 kJ
ii) Energy required to heat liquid Cu at 25°C to liquid Cu at
1084.5°C :
q₂ = n cp ∆T
= (1.45 mol) x (24.5 J/mol•°C) x (1084.5°C - 25°C)
= 37638.7 J
= 37.64 kJ
Total energy associated with recycling process
= (18.85 + 37.64) kJ
= 56.49 kJ
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11 Question (3 points) See page 247 Copper has been used for thousands of years, either...
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Copper has been used for thousands of years, either as a pure
metal or in alloys. It is frequently used today in the production
of wires and cables. Copper can be obtained through smelting or
recycling. Determine the energy associated with each of these
processes in order to recycle 1.32 mol Cu. The smelting of copper
occurs by the balanced chemical equation:
$$CuO(s)+CO(g)Cu(s)+CO2(g)
where ΔH°f,CuO is = –155 kJ/mol. Assume the
process of recycling copper is simplified to just the...
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