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11 Question (3 points) See page 247 Copper has been used for thousands of years, either as a pure metal or in alloys. It is f
2nd attempt Part 1 (1.5 points) & Feedback See Periodic Table O See Hint Enthalpy change for the reaction recovering Cu from
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Answer #1

Smelting:
CuO(s) + CO(g) ⟶ Cu(s) + CO₂(g)

Part 1:

∆H°f (Cu) = 0 kJ/mol , ∆H°f (CO₂) = -393.5 kJ/mol, ∆H°f (CuO​​​​​​​) = -155 kJ/mol, ∆H°f (CO​​​​​​​) = -110.5kJ/mol

∆H°rxn = Σ [∆H°f (products)] - Σ [∆H°f (reactants)]
= ∆H°f (Cu) +  ∆H°f (CO₂​​​​​​​) -  ∆H°f (CuO​​​​​​​) - ∆H°f (CO​​​​​​​)
= [0 + (-393.5)] - [-155 + (-110.5)] kJ/mol
= -128 kJ/mol

Enthalpy change associated with smelting 1.10 moles Cu :
∆H = (1.45 mol) x (-128 kJ/mol)
= -185.6 kJ

Hence, enthalpy change for the reaction recovering 1.45 mol Cu is -185.6 kJ

Part 2. Recycling:

i) energy required to convert solid Cu to liquid Cu at 25°C:
q = n ∆H°fus
= (1.45 moles) x (13.0 kJ/mol)
= 18.85 kJ

ii) Energy required to heat liquid Cu at 25°C to liquid Cu at 1084.5°C :
q = n cp ∆T
= (1.45 mol) x (24.5 J/mol•°C) x (1084.5°C - 25°C)
= 37638.7 J
= 37.64 kJ

Total energy associated with recycling process
= (18.85 + 37.64) kJ
= 56.49 kJ

Hope this helped! please upvote :)

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