Question

3. Acetic acid can be fermented anaerobically directly from glucose with the use of Clostridium bacteria C6H1206 = 3CH3COOH In an uncontrolled environment, a portion of this can form ethanol: C6H1206 = 2CH3CH2OH + 2002 If 500 kg of glucose is introduced into the fermenter and there is 52% conversion to acetic acid, 35 % conversion to ethanol and remainder unreacted, what will be the output of the fermenter on the molar basis?

Answer 1

Acetic acid and be fromented anaerobically from glucose Gothie De —> 364.000H In uncontrolled enviroment, ethanol is formed GH12 CHCHOH +2002 I moll of glucose produce a moles of acuticacid 180g of glucose produce 3x60 g of acetic acid 500 kg of glucose produce 500 x 3460 - 500kg of 180 actic acid for 100-1 conversion 500 kg is produce For 521 52x5A 10 kg of acette acid . 500 kg of glucose produce 110 Kg & acetic acid for 52-7- conversion. 1184 Imole of glucose produce a moles of ethanol 180 g g glucose produce 2446 g of ethanol 500 kg of glucose produce 500 x 2X41 - 180 For 100% conversion 255.6 Kg of ethanol 354. conversion 35x2556 89.46 kg of ethanol : 50 kg of glucose produce 89.5kg of ethanol for 351 conversion