Question

om/courses/24202/40122s/ Question 10 7 pts A motorcycle is moving at 16 m/s when its brakes are applied, bringing the cycle to rest in 3.5 s. To the nearest meter, how far does the motorcycle travel while coming to a stop?

Answer 1

initial velocity ,u =16m/s

final velocity ,v =0m/s

time =3.5s

First find deceleration

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Use formula v=u+at

$0m/s=16m/s+a*3.5s$

$0=16+a*3.5$

$a=-16/3.5=-4.571m/s^{2}$

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Use Formula $s=ut+1/2at^{2}$

$s=16m/s*3.5s-1/2*4.571m/s^{2}*(3.5s)^{2}$

$s=16*3.5-0.5*4.571*3.5^{2}$

ANSWER: ${\color{Red} s=28m}$

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