Question

The mean result from some experiment with 50 observations was 1.5 and the standard deviation was 1. Let $LaTeX: \mu$ μ denote the true mean result. We wish to to test $LaTeX: H_0\colon \mu=1$ H 0 : μ = 1 vs $LaTeX: H_a \colon \mu \neq 1$ H a : μ ≠ 1 . The p-value is

Group of answer choices

$LaTeX: 2 \times P(t_{49} \leq 3.5)$ 2×P(t49≤3.5)

$LaTeX: 2 \times P(t_{49} \geq \left|3.5\right|)$ 2×P(t49≥|3.5|)

$LaTeX: 2 \times P(t_{49} \leq -3.5)$ 2×P(t49≤−3.5)

$LaTeX: 2 \times P(t_{49} \leq \left|3.5\right|)$

Answer 1

Solution :

This is the two tailed test .

Test statistic = t

= ($\bar x$ - $\mu$ ) / s / $\sqrt$ n

= (1.5 - 1) / 1 / $\sqrt$ 50

Test statistic = 3.5

df = 50 - 1 = 49

The p-value is :

2 x P(t₄₉ > |3.5|)