Homework Answers
Below are the null and alternative Hypothesis,
Null Hypothesis: μ = 131
Alternative Hypothesis: μ > 131
Rejection Region
This is right tailed test, for α = 0.05 and df = 49
Critical value of t is 1.677.
Hence reject H0 if t > 1.677
Test statistic,
t = (xbar - mu)/(s/sqrt(n))
t = (133.474 - 131)/(11.193/sqrt(50))
t = 1.563
P-value Approach
P-value = 0.0622
As P-value >= 0.05, fail to reject null hypothesis.
There is not significant evidence to conclude that the mean
weekly grocery is not equals to 131.
It is equal to 131
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