A geyser shoots water directly upward to a height of 25.4 metres above the ground.
What is the initial velocity of the water, in m/s? (Take the acceleration due to gravity to be g = 9.81 m/s2 .)
height, h= 25.4 m
final veocity, v=0 m/s
Initial Velocity, u= ?
acceleration due to gravity, g= - 9.81 m/s2 (moving against the gravity)
v2=u2+2*g*h
0=u2+2*(-9.81)*25.4
u2 = 2*9.81*25.4
u=22.32m/s
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