Trey invested $72,000 in an account that pays 7.00 percent APR interest compounded quarterly (four times a year). How much money will he have at the end of 5 years?
| Solution: | ||||
| Money at end of 5 years =$101,864.03 | ||||
| Working Notes: | ||||
| C0 = Investment = $72,000 | ||||
| FV=Future worth of the investment after 5 years =?? | ||||
| r=rate of interest=APR/No of times compounded in a year = (7 %/4) =1.75% compounded quarterly | ||||
| n = no. Of periods = no. of years x No of times compounded in a year = 5 x 4 = 20 | ||||
| Using future value formula | ||||
| FV= C0 x (1+r)^n | ||||
| FV= $72,000 (1 + 1.75%)^20 | ||||
| FV = $72,000 (1 + 0.0175)^20 | ||||
| FV = 101,864.0301 | ||||
| FV = $101,864.03 | ||||
| Money at end of 5 years =$101,864.03 | ||||
| Please feel free to ask if anything about above solution in comment section of the question. | ||||
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