sample proportion, = 0.11
sample size, n = 300
Standard error, SE = sqrt(pcap * (1 - pcap)/n)
SE = sqrt(0.11 * (1 - 0.11)/300) = 0.0181
Given CI level is 99%, hence α = 1 - 0.99 = 0.01
α/2 = 0.01/2 = 0.005, Zc = Z(α/2) = 2.58
Margin of Error, ME = zc * SE
ME = 2.58 * 0.0181
ME = 0.0467
CI = (pcap - z*SE, pcap + z*SE)
CI = (0.11 - 2.58 * 0.0181 , 0.11 + 2.58 * 0.0181)
CI = (0.063 , 0.157)
Lower Bound = 0.063
Upper Bound = 0.157
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A simple random sample of size n = 400 individuals who are currently employed is asked if they work at home at least once per week. Of the 400 employed individuals surveyed, 42 responded that they did work at home at least once per week. Construct a 99% confidence interval for the population proportion of employed individuals who work at home at...
a simple random sample size n=250 individuals who are currently employed is asked if they work at home at least once per week. of the 250 employed individuals surveyed, 28 responded that they did work at home at least once per week. construct a 99% confidence interval for the population proportion of employed individuals who work from home atleast once per week. the lower bound is? the upper bound is?