Question

O CEMCAL REACTIONS Limiting reactants Kirst Aqueous hydrobromic acid (HBr) will react with solid sodium hydroxide (NaOH) to produce aqueous sodium bromide (NaBr) and liquid water (HO) Suppose 52. g of hydrobromic acid is mixed with 11.8 g of sodium hydroxide. Calculate the maximum mass of water that could be produced by the chemical reaction. Be sure your answer has the correct number of significant digits. x 5.?

Answer 1

Ans :

Mol HBr = mass HBr / molar mass

= 52 g / 80.9 g/mol = 0.643 mol

Mol NaOH = 11.8 g / 39.997 g/mol = 0.295 mol

Equimolar amounts of both the reagents are required in the reaction , here amount of NaOH is less , so NaOH is limiting reagent here.

Number of mol of water formed by 0.295 mol NaOH will be 0.295 mol

Mass of water formed = mol x molar mass

= 0.295 mol x 18.01528 g/mol

= 5.3 g